解决思路:以最大精度为标准同化精度再计算
addNum (num1, num2) {
let sq1,sq2,m;
try {
sq1 = num1.toString().split(".")[1].length;
}catch (e) {
sq1 = 0;
}
try {
sq2 = num2.toString().split(".")[1].length;
}catch (e) {
sq2 = 0;
}
m = Math.pow(10,Math.max(sq1, sq2));
return (num1 * m + num2 * m) / m;
},